You can use the subquery set membership test to compare a value from the main query to more than one value in the subquery.
The subquery set membership test compares a single data value for each row in the main query to the single column of data values produced by the subquery. If the data value from the main query matches one of the data values in the column, the subquery returns TRUE.
Select the names of the employees who head the Shipping or Finance departments:
SELECT GivenName, Surname FROM Employees WHERE EmployeeID IN ( SELECT DepartmentHeadID FROM Departments WHERE ( DepartmentName='Finance' OR DepartmentName = 'Shipping' ) ); |
GivenName | Surname |
---|---|
Mary Anne | Shea |
Jose | Martinez |
The subquery in this example extracts from the Departments table the ID numbers that correspond to the heads of the Shipping and Finance departments. The main query then returns the names of the employees whose ID numbers match one of the two found by the subquery.
SELECT DepartmentHeadID FROM Departments WHERE ( DepartmentName='Finance' OR DepartmentName = 'Shipping' ); |
The subquery set membership test is equivalent to the =ANY test. The following query is equivalent to the query from the above example.
SELECT GivenName, Surname FROM Employees WHERE EmployeeID = ANY ( SELECT DepartmentHeadID FROM Departments WHERE ( DepartmentName='Finance' OR DepartmentName = 'Shipping' ) ); |
You can also use the subquery set membership test to extract those rows whose column values are not equal to any of those produced by a subquery. To negate a set membership test, insert the word NOT in front of the keyword IN.
The subquery in this query returns the first and last names of the employees that are not heads of the Finance or Shipping departments.
SELECT GivenName, Surname FROM Employees WHERE EmployeeID NOT IN ( SELECT DepartmentHeadID FROM Departments WHERE ( DepartmentName='Finance' OR DepartmentName = 'Shipping' ) ); |
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